# Celestial bodies orbits

With this article, I want to review some aspect I have, up to now, explored by giving them a new, more organized, description.

You know from before that the sun runs a trajectory that can be sketched in a simplified way as a helix that has a cone shape with the bigger circle over the Capricorn tropic and the smaller circle over the Cancer tropic. You know all that even if the great majority of all flat Earthers don’t even know the same basic concept.  In the following table, we can see the radius and the height of the two extreme circles of the helix.

 Radius [Km] Height [Km] Cancer tropic 6660 6660 Capricorn tropic 13320 3330

Interesting is that we can decompose these values in a multiplication of factors like this:

6660=6x111x10

## Analyzing some order number

You find here three factors that will be now briefly analyzed. The same description will be valid also for the moon and the planets.

We can see that the number six is the one that better characterizes the sun orbit. But how can we classify this number? When you consider the position that all planets, sun and moon included, occupy over the flat Earth, you can immediately perceive that six is the order number of the sun. We have in fact this arrangement:  moon (9), Mercury (8), Venus (7), Sun (6), Mars (5), Jupiter (4), Saturn (3), Uranus (2), and Neptune (1). Then it’s something noteworthy that Pluto was resized down to a dwarf planet. So a rule that you can extract is that the sequence number of the celestial body characterizes some way its trajectory and we will discover many confirmations of this fact when discussing the planets.

## The number 111

The number 111 is the second number you have. I would like to call it the constant one which I will shorten as const1. The number 111 is really important. You know that on earth one latitude degree amounts to 111km. A degree of longitude on the Cancer tropic amounts to 111km, while half a degree on the tropic of Capricorn amounts to 111km. You also know the sun has a life cycle of 11 years 36 days that means 11.1 years. But, the most interesting thing to me, is that 111 can be obtained with the number 6. It is enough to square the six 62=36 and sum up all the numbers necessary to reach the square: 36+35+34+33+…+1=666. By dividing this value once more for 6 we can obtain our const1=111. To make it more elegant, all this process can be written with a single formula in order to generalize:

where n is the cipher  I want to call the order number of the celestial body, in this case, the sun.

In a calculation relative to the sun, as a middle result, you will obtain the value 666. This number, as we know since the beginning, is intrinsically linked with the measures of the sun and the Earth.

## A brief recap

But let’s remember how we obtained this number of 6660, which is linked to our 666. We started with Eratosthenes’s experience. He wanted to measure the circumference of the globe Earth and its radius: 6378 km. We know that in the flat geometry he measured not the radius of the Earth but the height of the sun. Moreover, we asserted that this height must be described with the number 6660 to describe the bigger fractal and to respect a mathematics we find in all creation. Let’s consider the number 10. We will call it const2. The possible meaning of this number will be explained further in this article, but let’s explain now how to calculate it. 6660 km is a number that we have obtained in many ways, passing through trigonometry, Demlo numbers, and Fractals. This is the number of the trajectory of the sun and becomes a reference for all other celestial bodies that, we will see, must have a cone near to that of the sun and very similar to it. 6660 becomes thus our reference point from which to calculate all other cones. From this value we can simply calculate the value 10 with a division: 10=6660/(111*6) that in a more generalized way becomes :

For the sun the formula is perfect. For the other celestial bodies, this formula will give a result with decimals. We will have to approximate the result to an integer value to obtain a coherent description of reality.

## The moon.

Let’s see the case of the moon. The moon has an order number n=9. Why 9 for the moon? Think to the sidereal cycle 0f 27,32 days (9×3 plus fractals) or to the libration in latitude lasting 18,5 years (9×2 plus fractals).

The first constant for the moon will be

The second constant will be:

As you can imagine, we have to approximate the value of the second constant. From n=9, const1=369, const2=2 we can now write all data of the cone of the moon in the following table. Since the cone of the moon doesn’t pass exactly on the tropics, I will call the two external orbits of the helix smaller orbit (the one near the Cancer tropic) and bigger orbit (the lower but bigger one near the Capricorn tropic).

 Radius [Km] Height [Km] Smaller orbit 9x369x2=6642 9x369x2=6642 Bigger orbit 9*369*4=13284 9x369x1=3321

We can immediately see that the cone of the moon is very near to the cone of the sun, only a little lower. It is clear that this is an approximated description: we describe only the bigger fractal. We know in fact that the cone of the moon is not always the same and oscillate from -5° to +5° around the cone of the sun, intersecting it every 18,5 years.

## Mercury

Let’s consider the calculation for each planet. I will report here only the calculations.

Mercury has order number n=8 (think for example that Mercury takes 88 days to do a complete turn around the sun).

The first constant is:

To find the second constant we have to consider that Mercury is an internal planet and we have thus to approximate by default:

We obtain the cone of Mercury:

 Radius [Km] Height [Km] Smaller orbit 8x260x3=6240 8x260x3=6240 Bigger orbit 8*260*6=12480 8x260x1.5=3120

## Venus

Venus has order number n=7.

We obtain the cone of Venus:

 Radius [Km] Height [Km] Smaller orbit 7x175x5=6125 7x175x5=6125 Bigger orbit 7x175x10=12250 7x175x2.5=3062.5

## Highlighting some interesting data

We have to stop a moment to highlight some interesting data. Mercury has order number n=8 while Venus n=7. We have given this order to the planets considering the order given in a classical geocentric model (see the picture). In this system, Mercury is the last planet. But, with the mathematics we are using, Mercury is no more the last one: Venus has a lower cone. Venus results to be, thus, the nearest planet to the Earth, and we can consequently explain its luminosity, while Mercury results to be the nearest to the sun, and this explains its fast movement around the sun, being strongly influenced by the solar wind. Someone could object that the moon is much near to the sun and also Mars is very near to the sun. Yes, but if you make a research on Mercury magnetosphere you will find that Mercury has a stable and significant magnetic field while the moon, as well as Mars, have nothing similar.

## Mars

Mars has order number n=5.

We have to approximate in excess because Mars is an external planet, so we have to obtain a cone that is higher than that of the sun.

We obtain the cone of Mars:

 Radius [Km] Height [Km] Smaller orbit 5x65x21=6825 5x65x21=6825 Bigger orbit 5x65x42=13650 5x65x10.5=3412.5

## Jupiter

Jupiter has order number n=4.

We have to approximate in excess of 51 to obtain a cone higher than that of Mars.

We obtain the cone of Jupiter:

 Radius [Km] Height [Km] Smaller orbit 4x34x51=6936 4x34x51=6936 Bigger orbit 4x34x102=13872 4x34x25.5=3468

## Saturn

Saturn has order number n=3

We have to approximate in excess to 155 to obtain a cone higher than that of Jupiter.

We obtain the cone of Saturn:

 Radius [Km] Height [Km] Smaller orbit 3x15x155=6975 3x15x155=6975 Bigger orbit 3x15x310=13950 3x15x77.5=3487.5

## Uranus and Neptune

For Uranus and Neptune the calculation loose precision but we do it to complete the job.

Uranus has order number n=2

We have to approximate in excess to 700 to obtain a cone higher than that of Saturn.

We obtain the cone of Uranus:

 Radius [Km] Height [Km] Smaller orbit 2x5x700=7000 2x5x700=7000 Bigger orbit 2x5x1400=14000 2x5x350=3500

Neptune has order number n=1

We have to approximate in excess to 7025 to obtain a cone higher than that of Uranus but the choice is completely aleatory.

We obtain the cone of Neptune:

 Radius [Km] Height [Km] Smaller orbit 1x1x7025=7025 1x1x7025=7025 Bigger orbit 1x1x14050=14050 2x5x3512.5=3512.5

## One last summary

Excluding the last two planets, we can make a summary of what we have found.

## The Titius-Bode Law

I believe that the highlighted numbers, our const 2 numbers are potentially very interesting and from this table, we can try to understand their significance. They represent a series that could remind you of the law of Titius.  The Titius-Bode Law is a rough rule that predicts the spacing of the planets in the Solar System. The relationship was first pointed out by Johann Titius in 1766 and was formulated as a mathematical expression by J.E. Bode in 1778. The law relates the mean distances of the planets from the sun to a simple mathematic progression of numbers.

Titius wrote:”Take notice of the distances of the planets from one another, and recognize that almost all are separated from one another in a proportion which matches their bodily magnitudes. Divide the distance from the Sun to Saturn into 100 parts; then Mercury is separated by four such parts from the Sun, Venus by 4+3=7 such parts, the Earth by 4+6=10, Mars by 4+12=16.

But notice that from Mars to Jupiter there comes a deviation from this so exact progression. From Mars, there follows a space of 4+24=28 such parts, but so far no planet was sighted there. But should the Lord Architect have left that space empty? Not at all. Let us, therefore, assume that this space, without a doubt, belongs to the still undiscovered satellites of Mars, let us also add that perhaps Jupiter still has around itself some smaller ones which have not been sighted yet by any telescope. Next to this for us, still unexplored space there rises Jupiter’s sphere of influence at 4+48=52 parts, and that of Saturn at 4+96=100 parts”.

## A quotation from Johann Elert Bode

And in 1772, in the second edition of his astronomical compendium, Johann Elert Bode wrote:

“This latter point seems, in particular, to follow from the astonishing relation which the known six planets observe in their distances from the Sun. Let the distance from the Sun to Saturn be taken as 100, then Mercury is separated by 4 such parts from the Sun. Venus is 4+3=7. The Earth 4+6=10. Mars 4+12=16. Now comes a gap in this so orderly progression. After Mars there follows a space of 4+24=28 parts, in which no planet has yet been seen. Can one believe that the Founder of the universe had left this space empty? Certainly not. From here we come to the distance of Jupiter by 4+48=52 parts, and finally to that of Saturn by 4+96=100 parts”.

## Doing some new hypothesis

Leaving apart these historical notations, when we consider 1 to be the distance of the earth from the sun (in a globular model) the distance of all planets can be described by this series:

0,39;   0,72;   1;   1,52;    5,20;   9,54;   19,18;  30,06;   39,51

Titius said that these values can be obtained with some approximation by writing this series of numbers:

0;        3;        6;        12;       24;       48;       96;        192

if you add 4 to each number and divide by 10:

0,4;      0,7;      1;       1,6;      2,8;      5,2;      10;       19,6

Could our red number be the new flat Earth Titius series?

2;         3;         5;          10;        21;        51;         155

It is certainly a fascinating hypothesis and I hope to reach soon the necessary knowledge and scientific proofs to validate or discard it.